Question

in the adjoining figure,x:y:z=5:4:6. if XOY is a straight line ,find the values of x,y and z​

Answer 1

x°+y°+z°=180°

let the multiple be a

5a+4a+6a=180°

15a=180

a=12

so,

x°=5×12=60°

y=4×12=48°

z=6×12=72°

Answer 2

Answer:

Step-by-step explanation:

Let x, y and z have a common factor p,

Then, according to the ques.,

x=5p, y=4p, z=6p

Now,

∠POX+∠POQ+∠QOY=180°                [XOY is a straight line]

⇒x+y+z=180°

⇒5p+4p+6p=180°

⇒p=12

So, x=5p=60°

      y=4p=48°

      z=6p=72°