Question

In the adjoining trapezium ABCD, it is being given that AD=20m. AB=CD, AE=12m and
BE=5m. The perimeter of the trapezium is:

Answer 1

if you look at the triangle

it is a right angled triangle

by Pythagoras thora

12^2+5^2=AB^2

144+25= AB^2

169= AB^2

13×13 = AB^2

AB = 13 = Dc

BC = BE+FC+EF

BC = 5+5+20

BC = 30m

perimeter = AB+BC+CD+DA

perimeter = 30+ 13 + 20 + 13

perimeter = 76m