in the adjoning fiqure ABCD is a square. the triangle BCEIs on the side BC
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plz attach the figure ty..
nilswa:
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But then what wet have to prove in this complete your question.
ABCD is a square and BCE is an equilateral triangle. The angle DCE = 90 + 60 or 150 degrees. Since BCE is an equilateral triangle, CE = CB = CD, so DEC is an isosceles triangle. So angle DEC = angle EDC = (180 - 150)/2 = 30/2 = 15 degrees.
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