in the AP the sum of first N terms is 3n2+n find the 22nd term
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5
a22=3×22×2+22=154
soa22=154
soa22=154
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8
In the given ap we have ,
An=3n2+n
Let n be 1
i.e. 3 (1) 2 + 1
6 + 1 = 7
First term = 7
Put n=2
3 (2) 2 + 2
12 + 2 = 14
Now , subtract 14-7 = 7
Plz check your question ..... i think u have copied wrong the textbook
An=3n2+n
Let n be 1
i.e. 3 (1) 2 + 1
6 + 1 = 7
First term = 7
Put n=2
3 (2) 2 + 2
12 + 2 = 14
Now , subtract 14-7 = 7
Plz check your question ..... i think u have copied wrong the textbook
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