Question

in the arrangement as shown in figure m1=1kg m2=2kg. pullies are massless and strings areb light. for what value of M the mass m1 moves with constant velocity?

Answer 1

Answer: M = 6  Kg

Given:

$m_1$ = 1 kg, $m_2$ = 2 kg  

Solution:

From the figure, total force acting on m1 is given by,

$m_1$g – $m_2$g = -g

negative sign indicates force is on upward direction

acceleration of $m_1$ is given by,

-g/$m_1$+$m_2$ = -g/3

Acceleration of total system is given by,

($m_1$+$m_2$)g/(M+$m_1$+$m_2$) = 3g/M+3

In order to achieve the constant velocity, the acceleration should be zero

                  3g/M+3 + (-g/3) = 0

                  3g/M+3 = g/3

                  9 = M+3

                  M = 6

Hence the total mass should be 6kg to achieve constant velocity.

Answer 2

Answer:8 kg is the answer to this ques

Treat each system separately to get correct ans

Explanation: