Question

In the arrangement shown in figure 1.19the mass........

Answer 1

4mg-2T =4ma/2=2ma
T-mg =ma
4mg - 2m(a+g) =2ma
4g-2a-2g =2a
a =1/2g
Now speed of mass m2 at d =2h
V^2 = 2as
V^2 =2*1/2*g*2h =2hg
V^2 =2gs
2hg = 2gs
S =h
So max h =2h+h =2h=3*0.2=0.6m

Answer 2

The following can be helpful tips for it:

▪Read question carefully answer in it only.

▪Just check wherter properties exsist or not.

▪Try to remind the things your mam has explained about the mass or get sured by your mam or say to revise it again.

▪You will be excellent at this question your othr friends will ask that how do you solved it a cleaver student will be your title at this question..

▪No answer just way to find answer.

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