Physics, asked by boscod040, 8 months ago

In the arrangement shown in figure
and Q of an inextensible string move downwards with
uniform speed u. Pulleys A and B are fixed. The mass
M moves upwards with a speed
(a) 2u cose (b) u/cose (c) 2u/cose (d) ucose.​

Answers

Answered by Anonymous
13

Explanation:

✍️ANSWER✍️

Let, V be the velocity of mass in upwards direction.

Therefore, component of velocity along the rope = VCosθ

Now, VCosθ=u

Therefore, V= u/Cosθ

Answered by pavit15
1

Answer:

Let speed of mass M be the V

 

the point on the thread just connected to mass M will have the same velocity  

the component v along the thread is vcosθ

 

the point of thread is moving with the speed of vcosθ as it is given in the thread moving with the velocity u

vcosθ is equal to u

 

V=  u/cosθ

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