Physics, asked by vanshikapundir8378, 1 year ago

In the arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible. Block of mass m 1 will remain at rest if:



(1) 1m1=1m2+1m3 (2) 4m1=1m2+1m3 (C) m 1 = m 2 + m 3 (D) 1m3=2m2+3m1

Answers

Answered by Anonymous
8

n the arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible.

The Block of mass m1 will remain at rest, if 4 / m1 = 1 / m2 + 1 / m3.

The right answer is 4 / m1 = 1 / m2 + 1 / m3.



Answered by abhinavszrobin
28

Answer:

4/m1 = 1/m2 + 1/m3

Explanation:

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