In the arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible. Block of mass m 1 will remain at rest if:
(1) 1m1=1m2+1m3 (2) 4m1=1m2+1m3 (C) m 1 = m 2 + m 3 (D) 1m3=2m2+3m1
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n the arrangement shown in figure, pulleys are massless and frictionless and threads are inextensible.
The Block of mass m1 will remain at rest, if 4 / m1 = 1 / m2 + 1 / m3.
The right answer is 4 / m1 = 1 / m2 + 1 / m3.
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Answer:
4/m1 = 1/m2 + 1/m3
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