Question

In the arrangement shown in figure, there is friction between the blocks of masses
m
and 2m which are in contact. The ground is smooth. The mass of the suspended
block is m. The block of mass m which is kept on mass 2m is stationary with respect
to block of mass 2m. The force of friction between m and 2m is (pulley and string are
lig frictionless)
​

Answer 1

Explanation:

Acceleration of the system of masses :–

$= \frac{net \: force}{total \: mass} = \frac{mg}{4m} = \frac{g}{4}$

now pseudo force will balance the frictional

force on the block A

so,

μmg = mg/4

μ = 1/4.

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