in the below figure, angle ABC= 59°,angle ACB= 41°, find angle BDC
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HERE IS THE ANSWER;
In triangle BAC
Angle A= Angle D【Angle on same segment 】..........1)
Now ,
Angle A +ABC +ACB = 180° 【Angle Sum Property】
Angle A + 59° + 41°=180°
Angle A=180°-59°-41°
=>Angle A=80°
There by equation 1)
Angle D is 80°. Answer
HOPE it helps
In triangle BAC
Angle A= Angle D【Angle on same segment 】..........1)
Now ,
Angle A +ABC +ACB = 180° 【Angle Sum Property】
Angle A + 59° + 41°=180°
Angle A=180°-59°-41°
=>Angle A=80°
There by equation 1)
Angle D is 80°. Answer
HOPE it helps
DonDj:
any doubt
Answered by
4
Answer:
80 °
Step-by-step explanation:
is it correct .... I just calculate in my mind
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