Question

In the below figure, if angle O
AB = 40°, then find angle ACB ​

Answer 1

Since OA=OB(Radius)

So

angleOAB=OBA

SO

OAB+OBA+AOB=180

40+40+AOB=180

AOB=100

SINCE ACB Is half of AOB

SO, ACB=AOB/2=100/2=50

SO ACB=50°

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