In the below figure, If EF=QR then the congruence rule used for the congruency of the given triangles is *
SAS test
ASA test
SSS test
Hypotenuse side test
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ASA will be the rule used for congruency in this condition, as angle E = angle Q.
Now in triangle PQR, angle P = 180 - (80+30) (sum of angles of a triangle) = 70.
Therefore, angle D = angle P.
Given EF = QR
Therefore, triangle DEF ~= triangle PQR by ASA
HOPE THIS HELPS ;)
Now in triangle PQR, angle P = 180 - (80+30) (sum of angles of a triangle) = 70.
Therefore, angle D = angle P.
Given EF = QR
Therefore, triangle DEF ~= triangle PQR by ASA
HOPE THIS HELPS ;)
Answered by
0
∆DEF
the answer is SAS
the answer is SASFD=SIDE
the answer is SASFD=SIDEDE=ANGLE
the answer is SASFD=SIDEDE=ANGLEEF=SIDE
NOW,∆PQR
RP=SIDE
RP=SIDEPQ=ANGLE
RP=SIDEPQ=ANGLEQR=SIDE
THE ANSWER IS SAS
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