Question

In the below figure, two equal circles, with centres O and O', touch each other at X.OO'
produced meets the circle with centre O' at A. AC is tangent to the circle with centre O, at the
point C. O'D is perpendicular to AC. Find the value of DO'/CO.

Answer 1

hey mate !!


AO =O'x = Ox



now ,


AO' = 3AO. -----------(1)




therefore .


traingle basic proposnality theroum


we get



A'O / AO = D'O / CO



3AO / AO = D'O / CO


therefore ,


D'O / CO = 1/3 .


hence the ratio will be 1:3 .


hope it helps!!!

thanks


brainly benefactor

@ ranjan Kumar

Answer 2

here is the answer

No need to mark me as brainliest as the above one answered first so he has the right..

But it was really great to solve it with you all..

Thanks..