Question

In the below given layout the design and measurement has been made such that area of two bedroom and kitchen is 95 sq.m
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Answer 1

Solution :-

→ Area of 2 bedrooms + kitchen = 95 m²

→ 2(5 * x) + (5 * y) = 95

→ 10x + 5y = 95

→ 5(2x + y) = 95

→ 2x + y = 19 ----------- Eqn.(1)

also,

→ x + 2 + y = 15

→ x + y = 15 - 2

→ x + y = 13 ---------- Eqn.(2)

therefore, (a) 2x + y = 19 and x + y = 13 pair of linear equations does describe this situation . (Ans.i)

now,

→ Outer boundary of layout = 2(L + B) = 2(15 + 12) = 2 * 27 = 54 m (d) . (Ans.ii)

and, solving Eqn.(1) and Eqn.(2)

→ 2(x + y) - (2x + y) = 2 * 13 - 19

→ 2x + 2y - 2x - y = 26 - 19

→ y = 7

putting value of y in Eqn.(2)

→ x + 7 = 13

→ x = 13 - 7

→ x = 6 .

then,

→ Area of Bedroom 1 = L * B = x * 5 = 6 * 5 = 30m² (b) . (Ans.iii)

therefore ,

→ Area of Living room = 7(2 + y) + x * 2 = 7(2 + 7) + 6 * 2 = 7 * 9 + 12 = 63 + 12 = 75 m². (c) (Ans.iv) .

hence,

→ cost of laying tiles in kitchen = Rate / m² * Area of kitchen = 50 * (5 * y) = 250 * 7 = Rs.1750 . (c) (Ans.v)

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