Question

In the bohr model of hydrogen atom,the electron circulates around the nucleus in a path of a radius 5.1×10^-11 m at a frequency 6.8×10^15 s^-1. Find the magnetic field set up at the centre of the orbit. (if you know the answer then tell otherwise don't type rubbish answers)​

Answer 1

Answer:

The magnetic field set up at the centre of the orbit is 13.3 weber/metre^2

Explanation:

According to the problem the electron circulates around the nucleus.

The frequency of the electron is,f=  6.8×10^15 s^-1

Therefore we can say that,

i =ef  [where e= the charge of the electron]

=6.8×10^15×1.6×10^(−19 )  

     =1.08×10^(−3)  amp

Therefore magnetic field at the center of the orbit,

B=μ0i/2r [ where r = the radius of the path]

=4π×10^(−7)×1.08×10^(−3)/2×0.51×10^(−10)

     =13.3 weber/m^2

Answer 2

Answer:

13.4 NA-1m-1

Explanation:

See the attached picture.