Question

In the bohr model, the electron of a hydrogen atom moves in circular orbit of radis 5.3xx10^-11 m with speed of 2.2xx10^6 m//s. Determine its frequency f and the current l in the orbit.

Answer 1

The frequency  will be 6.6x10¹⁵Hz and current will be 1.06mA.

Explanation:

We have to find the value of frequency

i.e

f = 1/T = $\frac{1}{T}$ . ......(1)             where T is the time period

Then given velocity v =  2.2x10⁶m/s

For distance d = 2πr,  where r is the radius of orbit.

then Time period will be T = $\frac{2\pi r}{v}$ then putting the value in equation (1)

f = $\frac{1}{T}$ = $\frac{v}{2\pi r}$ per second path travel

f = $\frac{2.2x10^{6} }{2\pi (5.3x10^{-11}) }$

f = 6.6x10¹⁵ Hz . This is the frequency.

To find the value of current  i = qxf

We have,

i = qxf =  1.6x10⁻¹⁹x6.6x10¹⁵

i = 1.06mA , value of current in the orbit