Question

In the case of a body freely falling from small height

1) The canges of position are equal in equal intervgals of time

2) The changes of velocity are equal in unequal interbvals of time

3) The changes of acceleration is zero in equal or unequal intervals of time

4) None​

Answer 1

Answer:

Consider time interval T∈(t

1

,t

2

) where t

2

−t

1

=c where c is a constant

Assume body is dropped from rest from a height h.

Displacement s=ut+

2

1

at

2

s=−

2

1

gt

2

Position at time t w.r.t ground x=h−

2

1

gt

2

Change in position in time interval T,Δx=

2

1

g(t

1

2

−t

2

2

)



=constant

v=u+at

v=−gt

Change in velocity in time interval T,Δv=g(t

1

−t

2

)=−gc=constant

Now,

g→const

∴ acceleration due to gravity is constant and the changes of acceleration is zero in equal intervals of time

Step-by-step explanation:

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Answer 2

Answer: Fourth is the correct because in the case of body freely we don't have nothing

Step-by-step explanation: