Question

In the circle with centre 'O' angle CAD=40 Find angle B and angle ACD?

Answer 1

Question :- In the circle with centre 'O' angle CAD=40 Find angle B and angle ACD ?

Solution :-

From image we have :-

• ∠CAD = 40°
• O is center of circle.

in ∆ADC , we have ,

→ AC passes through centre of circle.

So,

→ AC is diameter of circle.

Than,

→ ∠ADC = ∠ABD = 90° (Ans.) { Angle in semi - circle at the circumference is equal to 90° .}

now,

→ ∠CAD = 40° (given)

So,

→ ∠CAD + ∠ADC + ∠ACD = 180° (Angle sum property.)

→ 40° + 90° + ∠ACD = 180°

→ 130° + ∠ACD = 180°

→ ∠ACD = 180° - 130°

→ ∠ACD = 50° (Ans.)

Learn more :-

PQR is an isosceles triangle in which PQ=PR. Side QP is produced to such that PS=PQ Show

that QRS is a right angle

https://brainly.in/question/23326569

In triangle ABC, if AL is perpendicular to BC and AM is the bisector of angle A. Show that angle LAM= 1/2 ( angle B - an...

https://brainly.in/question/2117081