Question

IN the circuit below,calculate the net resistance of circuit. question no 5.

Answer 1

hey mate here is your answer ,,,

add resistance in series = 10 + 15 = 25 ohm

and next series resistance = 20+5 = 25 ohm

now add them in parallel = r1 +r2

          = 1/25 +1/25
          = 2/25
          = 25/2 = 12.5 ohm 

hence resultant resistance = 12.5 ohm

now , i = v/r
          i = 45/12.5
          i = 3.6 ampere

 hence net resistance is 12.5 ohm and current us 3.6 ampere 

 hope it helps ,,,,,,,,,,

Answer 2

.net resistance

= as this is series
=R=R1+R2
=10+15=25ohm
Let
R5=25ohm

same in 2nd connection
=R=R3+R4
=20+5=25ohm
LET
R6=25ohm
R=25ohm

NET RESISTANCE

as this both are in parallel connection
1/R=1/R5+1/R6
1/R=1/25+1/25
1/R=2/25
R=25/2

NET RESISTANCE=12.5ohm

HOPE IT HELPS