Question

In the circuit below, I1=5A, I3=7A, I4=6A, V1=5V, V2 =18V. Power delivered by the current source I1 is 90watts. Find the magnitude of I2

Answer 1

Given that,

Current in the circuit is

$I_{1}=5\ A$

$I_{3}=7\ A$

$I_{4}=6\ A$

Voltage in the circuit is

$V_{1}=5\ V$

$V_{2}=18\ V$

Power delivered by current source I₁ $P= 90\ Watt$

According to figure,

We need to calculate the magnitude of current I₂

Using kirchhoff's law

$-I_{1}+I_{2}-I_{3}+I_{4}=0$

$I_{2}=I_{1}+I_{3}-I_{4}$

Put the value into the formula

$I_{2}=5+7-6$

$I_{2}=6\ A$

Hence, The magnitude of current I₂ is 6 A.

Answer 2

Answer:18A

Explanation: Using Kirchoff's Current law at node 2,

I3 + I4 = Ix = 6 + 7

Ix = 13A

KCL at node 1,

I1 + Ix = I2 = 5 + 13

I2 = 18A