Question

in the circuit diagram , suppose the resistors R1, R2, and R3 hav a value 5ohm,10ohm and 30 ohm , which have been connected to a battery of 12 v. calculate the current throufh each resistor , the total current in the circuit and the total circuit resistance ?

Answer 1

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Answer 2

The answers are 2.4 A, 1.2 A, and 0.4 A respectively. The total current is 4 A and the total circuit resistance is 3 ohms.

Given:

R1 = 5

R2 = 10

R3 = 30

A battery of 12 V

To Find:

Calculate the current through each resistor, the total current in the circuit and the total circuit resistance

Solution:
As the resistors are in parallel, all the resistors have a voltage of 12 V across them. Hence by using Ohm's law

$V=IR$

we can get current through each resistor.

Current through R1 is

$I_1 = \frac{12}{5} =2.4A$

Current through R2 is

$I_2 = \frac{12}{10} =1.2A$

Current through R3 is

$I_3 = \frac{12}{30} =0.4A$

Hence the total current in the circuit will be the addition of all the currents, which is

$I=I_1+I_2+I_3 = 2.4+1.2+0.4=4A$

The total circuit resistance can again be given by Ohm's law,

$12=4R\\R=3$

Hence the current through each resistor is 2.4 A, 1.2 A, and 0.4 A respectively. The total current is 4 A and the total circuit resistance is 3 ohms.

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