Physics, asked by sujal332233, 11 hours ago

In the circuit given above, find i) The total current ii) Current flowing through 12Ω resistor iii) Total voltage in the circuit.

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Answered by anshuspider12

0

Answer:

sorry for to say I don't know the answer of this question

Explanation:

sorry sorry sorry

Answered by gc434652

1

When 8 and 12 are in parallel

and 7.2 is in series with them

Net Resistance 107.2+12+88×12

=1072+2096=1072+1048=10120=12Ω

Total current =netRV=126=0.5Ω

Voltage across R1=iR1=0.5×7.2=3.6

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