In the circuit given above, find i) The total current ii) Current flowing through 12Ω resistor iii) Total voltage in the circuit.
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When 8 and 12 are in parallel
and 7.2 is in series with them
Net Resistance 107.2+12+88×12
=1072+2096=1072+1048=10120=12Ω
Total current =netRV=126=0.5Ω
Voltage across R1=iR1=0.5×7.2=3.6
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