Question

in the circuit of the diagram given below find the equivalent resistance and total current flowing through the circuit​

Answer 1

See the attachment....

Answer 2

Given:

We have given a circuit diagram with a 6V battery and three resistance 3Ω, 4Ω and 2Ω.

To Find:

Using the given data we have to find equivalent resistance of the circuit and total current flowing through the circuit.

Solution:

From the diagram we get 4Ω and 2Ω are in parallel combination.

∴ $R_{equivalent 1}$ of  4Ω and 2Ω = $\frac{4\Omega \times 2\Omega}{4\Omega + 2\Omega}$ = $\frac{4}{3} \Omega$

Now, 3Ω is in series combination with $\frac{4}{3} \Omega$

∴ Resistance (total) of the circuit (R) = $3 \Omega + \frac{4}{3} \Omega$ = $\frac{13}{3} \Omega$

We, know that V = IR

∴ Total current flowing through the circuit ( I ) = $\frac{6 V }{ \frac{13}{3} \Omega }$ = $\frac{18}{13} A$

∴ Equivalent resistance of the circuit is $\frac{13}{3} \Omega$ and total current flowing through the circuit is $\frac{18}{13} A$.