Question

In the circuit shown below, a voltmeter of
resistance 6 ke is used to measure the voltage
drop across 3 k2 resistance, then the reading of
the voltmeter is
4 ko
www
20 V
3 k2​

Answer 1

Step-by-step explanation:

According to Ohm's law, V=IR. Therefore, the voltage is directly proportional to the resistance.

In this case, the voltage in the voltmeter V2 across 20 ohms is 80 V, so the voltage in the voltmeter V1 across the 40 ohms resistance will be 160 V.

Answer 2

Answer:

The reading of the voltmeter is $20V.$

Step-by-step explanation:

Resistance of the parallel combination of voltmeter $V(6k$Ω$)$ and $3k$Ω$R'=\frac{6k*3k}{6k+3k} =2$Ω

Current in the circuit,

$I=\frac{20}{2}=10A$

Reading on the voltmeter is,

   $=10*2=20V$