Question

In the circuit shown below C, = 10 uF, C2 = C3
20 uF, and CA = 40 uF. If the charge on C, is 20uC then potential difference between X and Y is
(IF YOU DON'T KNOW THE ANSWER DON'T ANSWER AND PLEASE GIVE EXPLANATION)​

Answer 1

Answer:

3V

Explanation:

From Figure :

C₁, C₂, C₃, C₄ are in parallel,

(C₁, C₂) and (C₃, C₄) are in series.

Let,

Q₁, Q₂, Q₃, Q₄ are charges on C₁, C₂, C₃, C₄.

Q₁/Q₂ = C₁/C₂

=> 20/Q₂ = 10/20

=> Q₂ = 40 uC

Now,

Total charge on positive plate of C₁ and  C₂ = 20+40 = 60 uC

pot difference across  Q₂ =  40/20 = 2V

Then,

Resultant of C₃,C₄ = 20+40= 60uF

Q = 60uC

difference across  Q₃ = 60/60 = 1V

difference between X and Y = 2V+1V = 3V

Therefore,

Potential Difference = 3 V.

Hope it helps!