In the circuit shown in figure, the current drawn from the circuit is 4Ampere. If 10 Ohm resister is replaced by 20 Ohm, then current drawn from the circuit will be?????
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Answered by
4
Answer:
don't thank me i googled it
Explanation:
Given circuit is a balanced Wheatstone bridge circuit. So there will be no change in equivalent resistance. Hence no further current will be drawn.
Answered by
0
Answer:
2Ampere
Explanation:
In 1st case
I - 4A
R - 10 Ohm
V -?
V=RI
V= 10×4
V = 40V
If Resistance 20 Ohm,
V - 40V
R-20 ohm
I = V/R
I = 40/20
I = 2Ampere
therefore the current drawn from the circuit is 2A when Resistance is 20 ohm.
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