Question

A car travels from A to B with the speed of
40 km h' and returns back on the same track at
same point with the speed of 60 km - Average
velocity will be
(1) 60 km -
12) Zero
(3) 48 km -
(4) 50 km h-1​

Answer 1

Answer:

Average velocity will be 0

Explanation:

Because

velocity = displacement/time

(Car travels from point A- B & return to point A . Then the displacement will be zero.)

If the displacement will zero then,

Velocity = 0/time

Velocity = 0

So, the average velocity will be zero.

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Answer 2

Answer:

Average velocity is 48km/h

Explanation:

The overall distance the object covers in a given amount of time is its average speed. A scalar value represents the average speed. It has no direction and is indicated by the magnitude.

The mean value of a body's speed over a period of time is its average speed. Since a moving body's speed is not constant over time and varies, the average speed formula is required. The values of total time and total distance travelled can be employed even when the speed varies, and with the aid of the average speed formula, we can identify a single value that sums up the entire motion.

Average speed formula when different speeds($s_{1},s_{2},s_{3},...............s_{n}$) given for same distance.

$S_{av} =\frac{n \times d}{d\times [\frac{1}{s1} +\frac{1}{s2} +....\frac{1}{sn} ]} \\\\=\frac{n}{ [\frac{1}{s1} +\frac{1}{s2} +....\frac{1}{sn} ]}$

Given: speeds

$s_{1} =40km/h\\s_{2} =60km/h$

Average Velocity

$S_{av} =\frac{2s_{1} s_{2}}{s_{1}+s_{2}} \\\\S_{av} =\frac{2\times40\times60}{40+60} \\\\S_{av} =\frac{2\times40\times60}{100}\\ S_{av} =48km/h$

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