In the circuit shown in figure, the current
through
39
22
A
B
222
w
89
89
422
9V
Lum
WWW
222
w
202
D
с
20
(1) the 32 resistor is 0.50 A
(2) the 3 2 resistor is 0.25 A
(3) the 4 12 resistor is 0.50 A
(4) the 4 2 resistor is 0.25 A
Answers
The total resistance of the circuit= 4+3+2=9 ohm
Potential difference= 9V
Since V=IR
I=9/9=1 A
1 A of current will pass through 3, 2 and simplified segment of 4 ohm resistor
Now expand the diagram, 1 A passes through BG , V = 1* 4= 4 V
Current in CF = 0.5 A
PD of CF = 0.5×4=2 V
Current in CDEF = 2/8=0.25 A
Therefore, current in 4 ohm resistor is 0.25 A
Is it correct, Arthur ?
The total resistance of the circuit= 4+3+2=9 ohm
Potential difference= 9V
Since V=IR
I=9/9=1 A
1 A of current will pass through 3, 2 and simplified segment of 4 ohm resistor
Now expand the diagram, 1 A passes through BG , V = 1* 4= 4 V
Current in CF = 0.5 A
PD of CF = 0.5×4=2 V
Current in CDEF = 2/8=0.25 A
Therefore, current in 4 ohm resistor is 0.25 A
Is it correct, Arthur ?
The total resistance of the circuit= 4+3+2=9 ohm
Potential difference= 9V
Since V=IR
I=9/9=1 A
1 A of current will pass through 3, 2 and simplified segment of 4 ohm resistor
Now expand the diagram, 1 A passes through BG , V = 1* 4= 4 V
Current in CF = 0.5 A
PD of CF = 0.5×4=2 V
Current in CDEF = 2/8=0.25 A
Therefore, current in 4 ohm resistor is 0.25 A
Is it correct, Arthur ?
Well net resistance = 9
current = 9/9 =1
option D is correct