in the circuit shown in figure the power developed in 6 ohm resistor is 24 what the power developed in 2 ohm resistor will be
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here you go mate,
The 6 and 12 ohm resistors are connected is parallel connection so we can directly write,
1/R3=1/r1+1/r2
=1/6+1/12 (LCM=12)
=2+1/12
=3/12
1/R=1/4
R=4 ohm.
The 4 and 2 ohm resistors are connected is parallel connection so we can directly write,
p=v²/r
⇒ p1/p2=r3/r4
⇒ 24/p2=4/2
⇒ 24/p2=2/1
⇒ By cross-multiplication,
2p2=24
p2=12 watt is the answer.
HOPE THIS HELP YOU!!
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