In the circuit shown in the figure, the current through
A. 3Ω resistor is 0.50 A
B. 3Ω resistor is 0.25 A
C. 4Ω resistor is 0.50 A
D. 4Ω resistor is 0.25A
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Gautam9501:
So what should we find?
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The total resistance of the circuit= 4+3+2=9 ohm
Potential difference= 9V
Since V=IR
I=9/9=1 A
1 A of current will pass through 3, 2 and simplified segment of 4 ohm resistor
Now expand the diagram, 1 A passes through BG , V = 1* 4= 4 V
Current in CF = 0.5 A
PD of CF = 0.5×4=2 V
Current in CDEF = 2/8=0.25 A
Therefore, current in 4 ohm resistor is 0.25 A
Hope that helps, Arthur!
Potential difference= 9V
Since V=IR
I=9/9=1 A
1 A of current will pass through 3, 2 and simplified segment of 4 ohm resistor
Now expand the diagram, 1 A passes through BG , V = 1* 4= 4 V
Current in CF = 0.5 A
PD of CF = 0.5×4=2 V
Current in CDEF = 2/8=0.25 A
Therefore, current in 4 ohm resistor is 0.25 A
Hope that helps, Arthur!
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