In the circuit shown in the figure, the current through A. 3Ω resistor is 0.50 A B. 3Ω resistor is 0.25 A C. 4Ω resistor is 0.50 A D. 4Ω resistor is 0.25A
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Given:
Voltage of the resistor = 9V
To Find:
The current through the resistor
Solution:
Net resistance of the circuit is = 9Ω.
Let total current be = I
Req = 2 + 2 + 4
= 8Ω
1/ Req = 1/8 + 1/8
= 8/2
= 4Ω
Req=3+4+2=9Ω
I = V/req
= q/q = 1
Current flowing through the 4Ω resistors
= I/4
= 1/4
= 0.25Ω
Answer: The value of 4Ω resistor is 0.25A
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