Question

In the circuit shown the charge on the 3F capacitor at steady state will be??

Answer 1

Answer:

(B) is the correct answer

Explanation:

in steady state:

We solve thi circuit we get current (I)= 1/3A

to find charge:

Va+1+1/3×1=Vb

Vb-Va=4/3,

chargé(q)=CV

q= c(Vb-Va)

q=3×4/3. (given C=3uF)

Chargé (q)= 4uC

Answer 2

Concept:

• Electric circuits
• Capacitors

Given:

• The net voltage V = 2V-1V = 1V
• The net resistance R= 1+2 = 3 ohm
• 3 μF capacitor

Find:

• The charge on the 3 μF capacitor at steady state

Solution:

At steady state, the current I is given by

I = V/R = 1/3

I = 1/3 A

Let the potential at the top left corner of the circuit = Va.

Let the potential at the bottom right corner of the circuit = Vb.

The potential difference across the  3 μF capacitor = Vb-Va

Va+ 1 + 1/3 = Vb

Vb-Va = 4/3

Q = CV

Q = 4/3 ×3

Q = 4 μC

The charge on the 3μF capacitor is 4μC. The correct option is b.

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