Question

In the circuit shown, the heat produced in the 5 ohm resistor due to current flowing through it, is 10 calories per second. Then the heat generated in the 4 ohm resistor is: ​

Answer 1

H = I2

Rt (H/t) = I2R for 5Ω,

(H/t) = 10 cal

∴ 10 = I12 × 5 I1 = √2A

Now V = I1(5) = I2(4 + 6)

∴ 5I1 = 10I2

∴ I2 = (I1/2) = (√2/2) = (1/√2)A

Hence heat in 4Ω resistor per second = (H/t) = I22

R = (1/√2)2 × 4 = 2 cal

hope it helps you

Answer 2

correct option (B) 2 calorie per sec Explanation: H = I2 Rt (H/t) = I2R for 5Ω, (H/t) = 10 cal ∴ 10 = I12 × 5 I1 = √2A Now V = I1(5) = I2(4 + 6) ∴ 5I1 = 10I2 ∴ I2 = (I1/2) = (√2/2) = (1/√2)A Hence heat in 4Ω resistor per second = (H/t) = I22 R = (1/√2)2 × 4 = 2