Question

In the circuit shown what will be reading of the ammeter long time after closing the key

Answer 1

The reading of the ammeter is 0.75 A.

Explanation:

Suppose, the voltage is 6 Volt and resistance is 8 ohm.

When the key is closed then the current is  flow in the circuit.

We need to calculate the reading of the ammeter

Using ohm's law

$V = IR$

$I=\dfrac{V}{R}$

Where, I = current

V = votage

R = resistance

Put the value into the formual  

$I=\dfrac{6}{8}$

$I=0.75\ A$

Hence, The reading of the ammeter is 0.75 A.

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Topic : ohm's law

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