Question

An 8 pole, 250v, wave wound generator has 400 conductors. if the generator is to be lap wound, the number of conductors required is

Answer 1

Given :

For wave wound generator

Number of pole = P =  8

Number of conductor = Z = 400

EMF = 250 volt

To Find :

If the generator is to be lap wound, the number of conductors required

Solution :

Let the number of conductors for lap wound = z

∵ EMF induced in armature = EMF = $\dfrac{P\Phi N}{60}$ × $\dfrac{Z}{A}$

where  -   P = number of pole

               N = number of coil turn

               A = number of parallel path

               Z = number o f conductor

                ∅ = flux per pole

Or,   EMF = k × $\dfrac{Z}{A}$

For wave wound generator

   A = 2

So,   EMF = k × $\dfrac{400}{2}$

Or,     EMF = k × 200

Or,  k = $\dfrac{250}{200}$ = 1.25

Again

For Lap wound generator

  A = number of pole = 8

So,  EMF = k × $\dfrac{z}{A}$

Or,   EMF = k × $\dfrac{z}{8}$

∵  EMF = 250 v  and  k = 1.25

So,   250 = 1.25 × $\dfrac{z}{8}$

Or,    $\dfrac{z}{8}$ = $\dfrac{250}{1.25}$

Or,  $\dfrac{z}{8}$ = 200

∴     z = 200 × 8

i.e   z = 1600

So, The number of conductor = z = 1600

Hence, if the generator is to be lap wound, the number of conductors required is 1600  . Answer