in the circuit , the current was measured to be 0.2A when voltage was 0.4V.And for voltage of 0.8 V , the corresponding current was 0.3 A .Find the resistance in the series.?
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Answer:
V=IR
where V stands for potential difference
I stands for current
R stands for resistance
for 0.4V
0.4=0.2×R
0.4/0.2 =0.2/0.2R
R=2ohms
for 0.8V
0.8= 0.3×R
0.8/0.3=0.3/0.3R
R=2.67ohms
those are the resistances
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