Question

in the class there are certain no of students.each student is given a toffee in such a way that First got 1 second got 2 and so on,if total no of chocolate is 630 distributed.how many student there.​

Answer 1

Answer:

Step-by-step explanation:

Ap formed = 1,2,3,.......

1st term, a = 1

Difference, d = 2-1 = 1

Sn = 630

N = ?

Sn = n/2 [2a + (n-1)d]

630 = n/2 [2×1 +(n-1)1]

630×2 = n[2 + n - 1]

1260 = n[1+n]

1260 = n+n²

N²+n-1260 = 0

N²+36n- 35n + 1260 = 0

N(n+36) -35(n+36) = 0

N-35 = 0. , n+36 = 0

N= 35. , n = -36

No. of students can't be -ve

So, total student = 35

Hope it helps uh

Plz mark as brainliest

Answer 2

HEY MATE HERE IS YOUR ANSWER

THE AP WILL BE :-

1,2,3...

A=1

D=1 ( a²-a¹)

Sn= 630

N= ?

SO BY THE SUM FORMULA OF AP :-

$sn = \frac{n}{2}(2a +( n - 1) \times d \\ \\ putting \: value \: \\ \\ 630 = \frac{n}{2}(2 \times 1 +( n - 1) \times 1 \\ \\ 630 \times 2 = n(2 + n - 1) \\ \\ 1260 = {n}^{2} + n \\ \\ {n}^{2} + n - 1260 \\ \\ = > {n}^{2} + 36n - 35n + 1260 \\ \\ (n - 35)(n + 36) \\ \\ = = > n = 35$

student can't be in negative so

[-35]