Question

In the diagram above,PQR is a tangent to the circle QSTW at point A.

•Find the value of x and y.​

Answer 1

Answer:

TQS=900 (angle in a semicircle)

∠STQ=∠SQR (angle in the alternate segment)

In Δ TQR,

∠QRS=x=180−(∠STQ+∠TQR)

=180−[40+(90+40)]

=180−170=100