In the diagram below find the lengths marked x and y. All dimensions are in cm. Answers which are not rational numbers should be given in square-root form.
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Cos 60 = x÷2
x = 4 ÷ √3
tan 60= AB÷2(let
let the altitude AB)
√3= ab /2
√3/2=ab
ab is common in both triangles
sin 30 =ab/y
1/2= √3/2y
1=√3/y
y=√3
I hope it works
x = 4 ÷ √3
tan 60= AB÷2(let
let the altitude AB)
√3= ab /2
√3/2=ab
ab is common in both triangles
sin 30 =ab/y
1/2= √3/2y
1=√3/y
y=√3
I hope it works
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0
the question you have typed is not correct data inadequate
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