In the diagram below find the lengths marked x and y. All dimensions are in cm. Answers which are not rational numbers should be given in square-root form.
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Answered by
1
Cos 60 = x÷2
![\frac{ \sqrt{3} }{2} = \frac{2}{x} \frac{ \sqrt{3} }{2} = \frac{2}{x}](https://tex.z-dn.net/?f=+%5Cfrac%7B+%5Csqrt%7B3%7D+%7D%7B2%7D++%3D++%5Cfrac%7B2%7D%7Bx%7D+)
x = 4 ÷ √3
tan 60= AB÷2(let
let the altitude AB)
√3= ab /2
√3/2=ab
ab is common in both triangles
sin 30 =ab/y
1/2= √3/2y
1=√3/y
y=√3
I hope it works
x = 4 ÷ √3
tan 60= AB÷2(let
let the altitude AB)
√3= ab /2
√3/2=ab
ab is common in both triangles
sin 30 =ab/y
1/2= √3/2y
1=√3/y
y=√3
I hope it works
Answered by
0
the question you have typed is not correct data inadequate
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