In the diagram, CE=12 units and BE=5 units.
Line l is a perpendicular bisector of line segment A C. It intersects line segment A C at point B. Line l also contains points D and E. Line segments A B and B C are the same length.
Based on the given information, what is AE?
2 units
7 units
12 units
17 units
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Given : CE=12 units and BE=5
AB = BC
To Find : AE
2 units
7 units
12 units
17 units
Solution:
∠ABE = ∠DBC = 90° vertically opposite angles
∠CBE = 180° - ∠ABE = 90°
in Δ CBE & ΔABE
∠CBE = ∠ABE = 90°
CB = AB given
BE = BE common
=> Δ CBE ≅ ΔABE (SAS)
=> CE = AE
=> AE = 12
AE = 12 unit
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