Question

In the diagram, given below, triangle ABC is right-
4
angled at B and BD is perpendicular to AC.
Find :(i) COS DBC
(ii) cot|DBA​

Answer 1

Answer:

AC^2=12^2+5^2=169

AC=13

using area of triangle

1/2*12*5=1/2*13*BD

BD=60/13

cosDBC=BD/BC=60/13*5=12/13

cosDBA=BD/BA=60/13*12=5/13