In the diagram O is the midpoint of the AB and ∠ BQO = ∠ APO . Show that ∠ OAP = ∠ OBQ
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Answer:-
given : -
O is the mid point of AB i.e. AO = BO
<BQO = < APO
To show :- <OAP = < OBQ
Solution :- In triangle AOP and triangle BOQ
AO = OB (given)
<AOP = < BOQ ( vertically opposite angles )
< APO = < BOQ (given)
By SAA congruence rule
triangle AOP ~= triangle BOQ
therefore, <OAP = <OBQ (by CPCT )
hence , proved
I hope it will help you out
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