Question

In the diagram the connected masses are pulled by a force of 400N. Find the acceleration of the system. Find the value of tension T.​

Answer 1

Given that,

• Force applied on the system = 400 N.
• Tension on the string = ?
• Masses in the system = 100kg, 200kg & 100kg.

Let's calculate acceleration,

According to the Newton second law of motion,

F = ma

where,

• F = 400 N
• a = ?

Mass = 100 kg + 200 kg + 100 kg = 400 kg.

Substitute the values in the above equation,

• 400 N = 400 kg × a
• a = 400 N / 400 kg
• a = 1 m/s^2.

Therefore, the acceleration is 1 m/s^2.

Let's calculate the Tension on thr string,

Here, T pulls only two masses (i.e.. 100kg & 200kg )

• Here, mass = 100 kg + 200 kg = 300 kg.
• Acceleration = 1 m/s^2.
• Force = ? ( here force is tension on thr string )

According to Newton's second law of motion,

• First = ma
• F = 300 kg × 1 m/s^2
• F = 300 N.

Therefore, the tension on the string is 300N.

Hope this helps you.

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