Question

In the distance between two (x,7) and (1,15)
10 find the value of x​

Answer 1

Explanation:

(x-1) ^2+(7-15)^2=100

(x-1) ^2=100-64

(x-1) ^2=36

x-1=6

x=7

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Answer 2

Answer:

LM = $\\ \sf{\sqrt {{( x2 - x1 )}^{2} + {(y2 - y1)}^{2}}}$

$\\ \longrightarrow \sf{10 = \sqrt {{( 1 - x)}^{2} + {(15 - 7)}^{2}}}$

$\\ \longrightarrow \sf{10 = \sqrt {{( 1 - x)}^{2} + {(8)}^{2}}}$

$\\ \longrightarrow \sf{10 = \sqrt {{( 1 - x)}^{2} + 64}}$

$\\ \longrightarrow \sf{100 = {( 1 - x)}^{2} + 64}$

$\\ \longrightarrow \sf{100 - 64 = {( 1 - x)}^{2}}$

$\\ \longrightarrow \sf{36 = {( 1 - x)}^{2}}$

Taking square root on both sides

$\\ \longrightarrow \sf{\sqrt {36} = \sqrt {{( 1 - x)}^{2}}}$

$\\ \longrightarrow \sf{ +\:or\:- 6 = 1 - x }$

$\\ \longrightarrow \sf{ 1 - x = 6\: or 1 - x = -6 }$

$\\ \longrightarrow \sf{ - x = 6 - 1 \: or \:- x = -6 - 1}$

$\\ \longrightarrow \sf{ - x = 5 \: or \:- x = -7}$

$\\ \longrightarrow \sf{ x = -5 \: or \: x = 7}$

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