Question

In the electrochemical cell :-
Zn | ZnSO₄ (0.01M) | | CuSO₄ (1.0 M) | Cu, the emf of this
Daniel cell is E₁. When the concentration of ZnSO₄ is changed to 1.0M and that of CuSO₄ changed to 0.01M, the emf changes to E₂. From the followings, which one is the relationship between E₁ and E₄?
(Given, $\frac{RT}{F}$ = 0.059)
(a) E₁ < E₂
(b) E₁ > E₂
(c) E₂ = 0 $\neq$ E₁
(d) E₁ = E₂

Answer 1

$<b>$
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$\mathbb{NICE...QUESTION}$

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In the electrochemical cell :-
Zn | ZnSO₄ (0.01M) | | CuSO₄ (1.0 M) | Cu, the emf of this
Daniel cell is E₁. When the concentration of ZnSO₄ is changed to 1.0M and that of CuSO₄ changed to 0.01M, the emf changes to E₂. From the followings, which one is the relationship between E₁ and E₄?
(Given, $\frac{RT}{F}$ = 0.059)
(a) E₁ < E₂
(b) E₁ > E₂
(c) E₂ = 0 $\neq$ E₁
(d) E₁ = E₂

→ [B]


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Answer 2

Answer :

_________________________

In the electrochemical cell :-

Zn | ZnSO₄ (0.01M) | | CuSO₄ (1.0 M) | Cu, the emf of this

Daniel cell is E₁. When the concentration of ZnSO₄ is changed to 1.0M and that of CuSO₄ changed to 0.01M, the emf changes to E₂. From the followings, which one is the relationship between E₁ and E₄?

(Given, \frac{RT}{F} = 0.059)

(a) E₁ < E₂

(b) E₁ > E₂

(c) E₂ = 0 \neq E₁

(d) E₁ = E₂

_______________________________-

The correct option is (b) :  E₁ > E₂

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hope it helps :)

thanks :)