Question

in the electrolysis of water a name the gas collected at anode and cathode. b why is the volume of gas collected at one electrode double than the other. c. what would happen if dil h2 o is not aades water

Answer 1

When electric current is passed through water , it decomposes to give hydrogen gas and oxygen gas.

                ELECTRICITY

2H₂O(I) ---------------------------- > 2H₂(g) + O₂(g)

At cathode :

H+ ions will gain electrons and form Hydrogen gas 

2H⁺ +2e--->H2 (g)

At anode : Oxygen gas will be released 

4 OH⁻(aq)→O2(g) + 2 H2O(l) + 4 e−

II) The volume of hydrogen gas collected at cathode is more than volume of oxygen gas at anode because water is made up of 2 parts of hydrogen and 1 part of oxygen by volume.

a) at cathode hydrogen is collect and at anode oxygen is collect

b) because in moleculer formual of water hydrogen Is double and their ratio is 2:1 so hydrogen Is double then oxygen

c) if we not add H2SO4 to water then water is become poor conducter because pure water is poor conductor and electrolysis is slow but when add sulfuric acid then it fast

iii) If dil.H2SO4 is added to water then the rate of electrolysis increases.

II) The volume of hydrogen gas collected at cathode is more than volume of oxygen gas at anode because water is made up of 2 parts of hydrogen and 1 part of oxygen by volume.

iii) If dil.H2SO4 is added to water then the rate

Answer 2

(a) at cathode H2 hydogen gas is collected and at anode oxygen gas get collected.

(b) Volume of H2 formed is doubled the volume of O2 because in H20 two moles of H atom is present whereas of Oatom only one.

I didn't understand the third question

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