Question

In the equation ax2+bx+c, if curve passes through (0,0), (-3,-4), (3,-4) then the value of a, b
and c is
a. a = 0, b = c = 0
b. a = 0, b = 0, C =-4/9
c. a=-4/9, b=0,c=0
d. a= -4/9,b = 0,C=-4/9​

Answer 1

Answer:

firt put (0, 0) on curve so we have C=0

now put (-3, -4) on curve so we have -6a-4b=0

now again put (3, -4) on curve so we have 6a-4b=0

now -6a-4b=0

6a-4b=0

________

0+8b=0

8b=0

b=0/8 =0 so b=0

now put the value of b in eq 2

6a-4b=0

6a-4×0=0

6a-0=0

6a=0

a=0/6=0 so a=0

so answer is a

Answer 2

Answer:

$a=-4/9, \,\,b=0\,\,\, and \,\,\,c=0$

Step-by-step explanation:

If any curve passes through any point then point must satisfy the given curve.

→ Putting point (0,0) we get value of c as zero;

$0 = a(0)^2 +b(0)+c \implies c=0$.

→Putting point (-3,-4) and (3,-4) we get equation as :

$-4 = a(-3)^2 +b(-3)+c \implies 9a-3b=-4.........(1)\\\\-4 = a(3)^2 +b(3)+c \implies 9a+3b=-4.........(2)$

On solving Equation  (1) and (2) we get:

a= -4/9 and b=0

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