Question

In the equation below, k>0, −(k+1)x+ky+5k=1 – 2ky ; when expressed in the form ax+by+c=0 gives c=4.The values of ‘a’ and ‘b’ are:

Answer 1

Answer:

a= 2/5 , b= 9/5 , c= 4

Step-by-step explanation:

=>Here,

−(k+1)x+ky+5k=1 – 2ky

(k+1)x-(k)y-5k =(2k)y-1

(k+1)x-(k+2k)y-(5k-1) =0

=>We know that, ax+by+c=0

a=k+1 , b= -3k , c= 1-5k

=>Let,

c= 4

1-5k= 4

5k= -3

k= -3/5

=> a= k+1= (-3/5)+1=(-3+5) /5 = 2/5

=> b= -3k= -3(-3/5)= 9/5

Answer 2

Answer:

a=0 b=3

Step-by-step explanation:

-(k+1)x+ky+5k=1-2ky

(k+1)x+(k)y-5k=(2k)y-1

(k+1)x-(k+2k)y-(5k-1)=0

In the question ax+by+c=0

a=(k+1)

b= -3k

c= 1-5k

c=6

1-5k=6

-5k=5

k= -1

a=(k+1)=(-1+1)=0

b= - 3k= - 3*-1=3