Math, asked by tjt, 1 year ago

In the equation x^2+mx+n=0 the only possible value of x is -3 so what is value of m

Answers

Answered by mstanwar
0
m=3+n/3
how
x=-3
so, -3^2-3m+n=0
9-3m+n=0
3(3-m)=-n
3-m=-n/3
-m=-n/3-3
m=3+n/3

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