Math, asked by athulnrao, 1 year ago

in the equation x²+2(k+2)x +9k =0 has equal roots, find k

Answers

Answered by PranavMudgal
16
Hey dear friend,

Equation=x²+2(k+2)x+9k=0

Compare with ax²+bx+c=0

a=1, b=2(k+2)=>(2k+4) and c=9k

By discriminant formula =>b²-4ac
Substituting values

=> (2k+4)²- 4*1*9k=0
=> 4k²+16+16k-36k=0
=>4k²-20k+16=0
Solving by factorisation
=>4k²-16k-4k+16=0
=>4k(k-4) -4(k-4)=0
=>(4k-4)(k-4)=0
4k-4=0. k-4=0
4k=4. k=4
k=1

So, the value of k can be 1 or 4.

perfectly fine pure correct answer
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PranavMudgal: bro if you have method then answer int his questions
athulnrao: the answer is correct
athulnrao: PranavMudgal
PranavMudgal: follow me athul
athulnrao: I have one more question
Anonymous: i have posted my answer
Anonymous: please check it and tell me wether it is correct or not mr. professor
PranavMudgal: correct bro
Anonymous: thank you
Anonymous: at last you agreed
Answered by Anonymous
3
this method is easier than the other one that mr. Pranav has done
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